2sin^2(2x)+2cos^2(2x)=0

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Solution for 2sin^2(2x)+2cos^2(2x)=0 equation: 


Simplifying
2sin2(2x) + 2cos2(2x) = 0

Remove parenthesis around (2x)
2in2s * 2x + 2cos2(2x) = 0

Reorder the terms for easier multiplication:
2 * 2in2s * x + 2cos2(2x) = 0

Multiply 2 * 2
4in2s * x + 2cos2(2x) = 0

Multiply in2s * x
4in2sx + 2cos2(2x) = 0

Remove parenthesis around (2x)
4in2sx + 2cos2 * 2x = 0

Reorder the terms for easier multiplication:
4in2sx + 2 * 2cos2 * x = 0

Multiply 2 * 2
4in2sx + 4cos2 * x = 0

Multiply cos2 * x
4in2sx + 4cos2x = 0

Reorder the terms:
4cos2x + 4in2sx = 0

Solving
4cos2x + 4in2sx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4in2sx' to each side of the equation.
4cos2x + 4in2sx + -4in2sx = 0 + -4in2sx

Combine like terms: 4in2sx + -4in2sx = 0
4cos2x + 0 = 0 + -4in2sx
4cos2x = 0 + -4in2sx
Remove the zero:
4cos2x = -4in2sx

Divide each side by '4os2x'.
c = -1in2o-1s-1

Simplifying
c = -1in2o-1s-1

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